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>DISPLAY 7 SEGMENT

15 Jun

>Seven segment display   7-Segment Displays
Truth Table to Decode Binary into 7-Segment

Decimal
Number
Inputs Outputs
D C B A a b c d e f g
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
1
0
1
1
01
1
1
1
1
1
1
1
1
10
0
1
1
1
1
1
0
1
11
1
1
1
1
1
0
1
1
01
1
0
1
1
1
0
1
0
00
1
0
1
0
1
0
0
0
11
1
0
1
1
0
0
1
1
11
1
0
1
1

Layout of 7-segment display 

Karnaugh Mapping for Segment a:
The Truth Table:

BA  00   01   11   10 
DC\
 00  1 0 1 1
 01  0 1 1 1
 11  x x x x
 10  1 1 x x

Boxing ones:

BA  00   01   11   10 
DC\
 00  1 0 1 1
 01  0 1 1 1
 11  x x x x
 10  1 1 x x

Red cells are represented by B; this is a 4×2 supercell.

BA  00   01   11   10 
DC\
 00  1 0 1 1
 01  0 1 1 1
 11  x x x x
 10  1 1 x x

Green cells are represented by D; this is a 2×4 supercell.
So far then we have:

BA  00   01   11   10 
DC\
 00  1 0 1 1
 01  0 1 1 1
 11  x x x x
 10  1 1 x x

where grey boxes indicate cells included in more that one supercell.The shaded boxes are represented by B+D.
Focusing on the remaining cells with ones:

BA  00   01   11   10 
DC\
 00  1 0 1 1
 01  0 1 1 1
 11  x x x x
 10  1 1 x x

Blue cells are represented by A.C; this is a 2×2 supercell.

BA  00   01   11   10 
DC\
 00  1 0 1 1
 01  0 1 1 1
 11  x x x x
 10  1 1 x x

Cyan cells are represented by A’.C’; this is a 2×2 wrap-around supercell.

BA  00   01   11   10 
DC\
 00  1 0 1 1
 01  0 1 1 1
 11  x x x x
 10  1 1 x x

All cells are represented by B + D + A.C + A’.C’,as shown for segment a.
Karnaugh Mapping for Segment c:
The Truth Table:

BA  00   01   11   10 
DC\
 00  1 1 1 0
 01  1 1 1 1
 11  x x x x
 10  1 1 x x

Boxing zeroes:

BA  00   01   11   10 
DC\
 00  1 1 1 0
 01  1 1 1 1
 11  x x x x
 10  1 1 x x

The red cells are represented by C’.B.A’;of course the complement is required for the final realization.Thus (C’.B.A’)’ is the combination of gates thatis realized from the Karnaugh mapping of zeroes.Application of De Morgan’s theorem results in the combination of gatesshown for segment c:
(C’.B.A’)’ = C + B’ + A

Seven segment display   Decoder for segment a
Layout of 7-segment decoder

D C B A a
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
1
0
1
1
01
1
1
1
1
       

Seven segment display   Decoder for segment b
Layout of 7-segment decoder

D C B A b
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
1
1
1
1
10
0
1
1
1

Seven segment display   Decoder for segment c
Layout of 7-segment decoder

D C B A c
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
1
1
0
1
11
1
1
1
1
       
BA  00   01   11   10 
DC\
 00  1 1 1 0
 01  1 1 1 1
 11  x x x x
 10  1 1 x x

Karnaugh

Seven segment display   Decoder for segment d
Layout of 7-segment decoder

D C B A d
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
1
0
1
1
01
1
0
1
1

Seven segment display   Decoder for segment e
Layout of 7-segment decoder

D C B A e
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
1
0
1
0
00
1
0
1
BA  00   01   11   10 
DC\
 00  1 0 0 1
 01  0 0 0 1
 11  x x x x
 10  1 0 x x

 

Seven segment display   Decoder for segment f
Layout of 7-segment decoder

D C B A f
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
1
0
0
0
11
1
0
1
1
 

Seven segment display   Decoder for segment g
Layout of 7-segment decoder

D C B A g
0
1
2
3
45
6
7
8
9
0
0
0
0
00
0
0
1
1
0
0
0
0
11
1
1
0
0
0
0
1
1
00
1
1
0
0
0
1
0
1
01
0
1
0
1
0
0
1
1
11
1
0
1
1
 
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Ditulis oleh pada Selasa, Juni 15, 2010 in Uncategorized

 

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